1/(2^x)=5

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Solution for 1/(2^x)=5 equation: 



1/(2^x)=5

We move all terms to the left:

1/(2^x)-(5)=0



Domain of the equation: 2^x!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


-5*2^x+1=0

Wy multiply elements

-10x+1=0

We move all terms containing x to the left, all other terms to the right

-10x=-1

x=-1/-10

x=1/10

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